Write a method named minGap hat accepts an integer array as

Write a method named minGap (hat accepts an integer array as a parameter and returns the minimum \'gap\' between adjacent values in the array. The gap between two adjacent values in a array is defined as the second value minus the first value. For example, suppose a variable called array is an array of integers that stores the following sequence of values: int[] array - {1, 3, 6, 7, 12); The first gap is 2 (3 - 1), the second gap is 3 (6 - 3), the third gap is 1 (7 - 6) and the fourth gap is 5 (12 - 7). Thus, the call of minGap (array) should return l because that is the smallest gap in the array. If you are passed an array with fewer than 2 elements, you should return o. You should submit: Java code Screenshot of the output of your program.

Solution

Hi, Plesae find my code.

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public class MinGap {

  

   public static int minGap(int[] arr){

      

       // base case

       if(arr == null || arr.length < 2)

           return 0;

      

       int mingap = arr[1] - arr[0]; // initializing min gap

      

       for(int i=2; i<arr.length; i++){

          

           int currGap = arr[i] - arr[i-1];

          

           if(mingap > currGap)

               mingap = currGap;

       }

      

       return mingap;

   }

  

   public static void main(String[] args) {

      

       int arr[] = {1, 3, 6, 7, 12};

      

       int minGap = minGap(arr);

      

       System.out.println(\"Min Gap: \"+minGap);

   }

}

/*

Sample Output:

Min Gap: 1

*/