Homework SourseFind any critic numbers for f and then use the second deriva
Find any critic numbers for f and then use the second derivative test to decide whether the critical numbers lead to a relative max or minute.
F(x) = x^7/3 +x^4/3
F(x) = x^7/3 +x^4/3
Solution
x=0 gives a saddle point and x = -0.83 gives a relative maximum. 7*x^6/3+4*x^3/3=0 7*x^6=-4*x^3 x=0 or x^3=-4/7 x=-.83 second derive:14*x^5+4*x^2 is 0 at x=0 so is neither relative minimum nor maximum, but a saddle point. is neg when x=-.83 so rel max
