oo Verizon LTE 509 PM 1196 sessionmasteringphysicscom C Prob

oo Verizon LTE 5:09 PM 1196 session.masteringphysics.com C Problem 18.29 MasteringPhysics 7 of 18 Problem 18.29 A 5.80 m × 8.00 m × 2.50 m room contains air at 20° C. Part A What is the room\'s thermal energy? Express your answer with the appropriate units. Value Unis Submit Give Up Continue >

Solution

volume of the room,

V = 5.8*8*2.5 = 116 m3

So,

number of moles of gas in the room,

n = 0.0224*116 = 2.598 moles

So, the number of molecules in the room:

N = 2.598*6.022*10^23 = 1.56*10^24

So, the thermal energy of the room:

KEt = N*(3/2)*k*T

= 1.56*10^24*(3/2)*1.38*10^-23*(273.2 + 20)

= 9.47*10^3 J