Par Inc is a manufacturer of golf equipment and has develope
Par, Inc. is a manufacturer of golf equipment and has developed a new golf ball that has been designed to provide extra distance.? In a test of driving distance using a mechanical driving device, a sample of Par golf balls was compared with a sample of golf balls made by Rap, Ltd., a competitor. We want to determine whether or not there is a significant difference between the two balls
| Current | New | 
|---|---|
| 264 | 299 | 
| 261 | 269 | 
| 267 | 285 | 
| 272 | 266 | 
| 258 | 262 | 
| 283 | 301 | 
| 258 | 262 | 
| 266 | 289 | 
| 259 | 286 | 
| 270 | 235 | 
| 263 | 274 | 
| 264 | 266 | 
| 284 | 295 | 
| 263 | 271 | 
| 260 | 260 | 
| 283 | 304 | 
| 255 | 250 | 
| 272 | 263 | 
| 266 | 215 | 
| 268 | 264 | 
| 270 | 272 | 
| 278 | 304 | 
| 289 | 264 | 
| 280 | 280 | 
| 298 | 287 | 
| 275 | 281 | 
| 305 | 276 | 
| 260 | 289 | 
| 233 | 268 | 
| 275 | 262 | 
| 281 | 283 | 
| 274 | 250 | 
| 273 | 253 | 
| 263 | 260 | 
| 275 | 270 | 
| 267 | 263 | 
| 223 | 261 | 
| 274 | 255 | 
| 289 | 263 | 
| 262 | 279 | 
Solution
Sample #1 Sample #2
Par, Inc. Rap, Ltd.
Sample Size n1 = 120 balls n2 = 80 balls
Mean = 235 yards = 218 yards
Standard Deviation s1 = 15 yards s2 = 20 yards
Point Estimate of the Difference Between Two Population Means
m1 = mean distance for the population of
Par, Inc. golf balls
m2 = mean distance for the population of
Rap, Ltd. golf balls
Point estimate of m1 - m2 = = 235 - 218 = 17 yards.
95% Confidence Interval Estimate of the Difference Between Two Population Means: Large-Sample Case, s1 and s2 Unknown
Substituting the sample standard deviations for the population standard deviation:
X1-x2+ z sqrt (sigma1^2 /n1 + sigma2^2 /n2 )=17+ - 1.96 sqrt (15^2 /120 + 20^2 /80)
= 17 + 5.14 or 11.86 yards to 22.14 yards.
We are 95% confident that the difference between the mean driving distances of Par, Inc. balls and Rap, Ltd. balls lies in the interval of 11.86 to 22.14 yards


