Concept Map Given potential B determine velocity IE Jx lEy

Concept Map: Given potential & B, determine: velocity, IE>, Jx, lEy, Rh. Note: conductive box corners are assumed split so sides of boxes below are isolated (not To Do: 1) Consider each case 1 of 4 cases below. Case (1) Direction positive charges would move velocity. Gradient of potential. Direction electrons would move velocity. JX for each case. (direction positive chg moves) Indicate whereor- would plié up. Ey, Rh O \' 2 O V applied 0 1 B Case (2) Direction positive charges would move... velocity Gradient of potential Direction electrons would move... velocity Jx for each case. Indicate where +or- would plié up. Ey, Rh V applied Case (3) Direction positive charges would move...velocity Gradient of potential Direction electrons would move... velocity Jx for each case. Indicate whereor-would plié up. Ey, Rh 21 V applied

Solution

PART A

FOR CASE 1

v12 is negative that is at side 1 (at top) accumlation of negative charge (electron)(apply flamming left hand rule). Thus majority carriers are electron.hence it N type material.

PART b

for negative charge accumlation of negative charge at top direction of magnetic field should be outward.

in fig 1 magnetic field direction is shown correct for negative charge

same will be for diagram 4 only difference is direction of current and magnetic field chnaged. material will be N TYPE SEMICONDUCTOR

PART C

in diagram 2 and 3 for negative charge v12 will be positive that is greater than 0