For a particular genetic strain of corn you suspect that abn
Solution
Expected number
e
d
(o-e)
Expected value can be calculated by dividing the total number 100 by the number of phases 4
So the expected value will be 25.
a) The Chi-Square value is 3.28
Degrees of freedom is n-1 ie 4-1=3
P- value from the chi- square distribution table is 0.223
b) Null hypothesis H0
The chi-square distribution value is between the range of 0.50 and 0.25. When compared to the significant value, P value is greater than the significant value. Hence H0 is not rejected in this case as the obtained range is not less than 0.05 and it is considered not significant.
c) The chi-square distribution clearly states that the observed data does not fit the Mendel\'s principle of segregation as the results observed are insignificant
| Mitotic phase | Observed number | Expected number e | d (o-e) | d2 | d2/e |
| Prophase I | 30 | 25 | 5 | 25 | 1 |
| Metaphase I | 20 | 25 | -5 | 25 | 1 |
| Anaphase I | 21 | 25 | -4 | 16 | 0.64 |
| Telophase I | 29 | 25 | 4 | 16 | 0.64 |
| Total | 100 | 3.28 |
