A car is traveling at 50 mih when the brakes are fully appli

A car is traveling at 50 mi/h when the brakes are fully applied, producing a constant deceleration of 34 ft/s2. What is the distance covered before the car comes to a stop? (Round your answer to one decimal place.)

Solution

1 mi = 5280 feet 1hr = 3600sec u = 5280*50/3600 ft/sec = 73.3333 ft/sec also a = - 34ft/sec^2 so, let say the distance cover is \'s\' when the vehicle stops v^2 = u^2 + 2s*a 0 = (73.3333)^2 + 2 * (-34)*s s = ((73.3333)^2) / (68) s = 79.1 ft
A car is traveling at 50 mi/h when the brakes are fully applied, producing a constant deceleration of 34 ft/s2. What is the distance covered before the car come

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