Question 1 ContinuedSolutionFrom the stem and leaf plot we h
Question 1 Continued
Solution
From the stem and leaf plot we have to find median lower quartile.
Here N = 132
Median = [ ( (N/2) + (N/2 +1)th ) / 2 ]th observation.
= [ ( (132 / 2)th + (132 +1)th ) /2 ]observation
= ( 66 th observation + 67th observation ) / 2
= (5 + 5) / 2 = 10 / 2 = 5
Median = 5
Lower quartile is nothing but Q1 or first quartile.
Lower quartile = (N / 4)th observation in the data
= (132 / 4) th observation in the data
= 33 rd observation in the data
= 10
Lower quartile is 0.
The probability that a female driver stops beyond the stopping line is estimated directly from the data by,
Probability = number of negative values / total number of values
= 34 / 132 = 0.2576
![Question 1 ContinuedSolutionFrom the stem and leaf plot we have to find median lower quartile. Here N = 132 Median = [ ( (N/2) + (N/2 +1)th ) / 2 ]th observatio Question 1 ContinuedSolutionFrom the stem and leaf plot we have to find median lower quartile. Here N = 132 Median = [ ( (N/2) + (N/2 +1)th ) / 2 ]th observatio](/WebImages/17/question-1-continuedsolutionfrom-the-stem-and-leaf-plot-we-h-1032942-1761535567-0.webp)