Question 1 ContinuedSolutionFrom the stem and leaf plot we h

Question 1 Continued

Solution

From the stem and leaf plot we have to find median lower quartile.

Here N = 132

Median = [ ( (N/2) + (N/2 +1)th ) / 2 ]th observation.

= [ ( (132 / 2)th + (132 +1)th ) /2 ]observation

= ( 66 th observation + 67th observation ) / 2

= (5 + 5) / 2 = 10 / 2 = 5

Median = 5

Lower quartile is nothing but Q1 or first quartile.

Lower quartile = (N / 4)th observation in the data

= (132 / 4) th observation in the data

= 33 rd observation in the data

= 10

Lower quartile is 0.

The probability that a female driver stops beyond the stopping line is estimated directly from the data by,

Probability = number of negative values / total number of values

= 34 / 132 = 0.2576

Question 1 ContinuedSolutionFrom the stem and leaf plot we have to find median lower quartile. Here N = 132 Median = [ ( (N/2) + (N/2 +1)th ) / 2 ]th observatio

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