Homework Soursethe area of a rectangle is decreasing at the rate of 03m2hr
the area of a rectangle is decreasing at the rate of 0.3m^2/hr. at each moment the width of the rectangle is twice its height. when the area of the rectangle is 2m^2, the rate of change of the perimeter is)?
Solution
w=2h area=wh=2h^2 dA/dt=4hdh/dt=0.3 dh/dt=0.3/4 area=2 so h=1 rate of change of perimeter=2d(w+h)/dt 6dh/dt =6*0.3/4 =0.45
