A multiloop circuit is shown in the figure Find the currents
Solution
Apply Kirchoff\'s second law to adeba loop you get ,
24 = 13 i1 +5(5)+3(2)
= 13 i1 +25 +6
=13 i1 + 31
13 i1 = 24-31
= -7
i1 = -7/13 = -0.5384 A
Apply Kirchoff\'s second law to degfd loop you get , 5(5)= 20 -E1
E1 = 20 -25 = -5 volt
Apply Kirchoff\'s seond law to bchgec loop you get ,
E2-20 = -4(i3)+3(2)
E2 = -4i3 +6 +20
= -4i3 +26 ---------( 1)
Apply Kirchoff\'s second law to abchgfda loop you get ,
-24 +E2 -E1 = -4 i3 -13 i1
-24 +E2 -(-5) = -4 i3 -13 ( -0.5384)
-19 +E2 = -4i3 + 7 ---------------------( 1)
Apply Kirchoff\'s first law to junction e you get ,
5 A = 2 A + i2
i 2 = 5A-2A= 3A
Apply Kirchoff\'s first law to junction d you get ,
5 A +i4 = i1
= -0.5384 A
i4 = 5.5385 A
Apply Kirchoff\'s first law to junction g you gte , i3 = i4 + i2
i3 = 5.5385 +3
= 8.5385 A
Substitute this value in equation( 1) you get ,
-19 +E2 = -4(8.5385) + 7
= -27.154
E2 = -27.154 +19
= -8.154 volt

