Peak current in a cyclic voltammogram is 33 A The electrode

Peak current in a cyclic voltammogram is 3.3 A. The electrode area is 0.45 cm², the diffusion coefficient for the redox couple is 9 x 10^-6 cm²/sec, and the scan rate is 50 mV/sec. Assuming that you began with only the oxidized species and scanned negatively and that n=1, calculate the concentration of the oxidized species in the bulk solution in mol/L.

Solution

The peak current is given by the equation:

i_p = 2.69x10⁵n^3/2ACD^1/2v^1/2

^{here A} is the area Cis concentration,D is diffusion coefficient and v is scan rate

putting all values in the equation

3.3x10^-6 (Amp) =2.69x10⁵ *1*0.45(cm² )*C *3*10^-3 cm/sec^1/2 *(50/1000)^1/2 volt^1/2/sec^1/2

3.3x10^-6 (Amp)=81.20*C(cm³volt^1/2/sec)

C=0.0406 (amp sec /cm³ volt ^1/2) =0.0406mol/mL=0.0406*10³ mol/L