Probability and genetic counseling OPEN BOXES OR CIRCLES ARE

Probability and genetic counseling (OPEN BOXES OR CIRCLES ARE NORMAL PHENOTYPE; CLOSED BOXES OR CIRCLES ARE ALBINO) Please calculate the probability to produce albino through the each individual cross. (10%) 6 times 12 = (15%) 4 times 5 = (15%) 6 times 10 = (15%) 7 times 14 = (15%) 2 times 10 = (15%) 2 times 12 = (15%) 3 times 9 =

Solution

Probability and genetic counselling (open boxes or circles are normal phenotype ; closed boxes or circles are blind )IT IS RECESSSIVE TRAIT

IT REQUIRED DOUBLE DOSE OF RECESSIVE ALLELES FOR EXPRESSION

I generation    Parental

1

Normal    heterozygous-genotype   Aa

2

Affected    homozygous-genotype   aa

2 generation   

1

Normal    heterozygous-genotype   Aa

2

Normal    heterozygous-genotype   Aa

3

Normal    homozygous-genotype   AA

4

Affected    homozygous-genotype   aa

5

Normal    heterozygous-genotype   Aa

6

Normal    heterozygous-genotype   Aa

7

Normal    heterozygous-genotype   Aa

8

Normal    homozygous-genotype   AA

=========

3 generation

6 x 12

III-6 genotype   Aa x III-12 genotype   Aa

A

a

A

AA

Aa

a

Aa

aa

Probability of albino= ¼= 0.25--------------answer

============================================================

III-4 genotype   aa x III-5 genotype   Aa

a

a

A

Aa

Aa

a

aa

aa

Probability of albino= 1/2= 0.50--------------answer

==================================================================================

III-6 genotype   Aa x III-10 genotype   Aa

A

a

A

AA

Aa

a

Aa

aa

Probability of albino= ¼= 0.25--------------answer

III-7 genotype   Aa x III-14 genotype   Aa

A

a

A

AA

Aa

a

Aa

aa

Probability of albino= ¼= 0.25--------------answer

============================================================

III-2 genotype   Aa x III-12 genotype   Aa

A

a

A

AA

Aa

a

Aa

aa

Probability of albino= ¼= 0.25--------------answer

III-3 genotype   Aa x III-9 genotype   Aa

A

a

A

AA

Aa

a

Aa

aa

Probability of albino= ¼= 0.25--------------answer

I generation    Parental

1

Normal    heterozygous-genotype   Aa

2

Affected    homozygous-genotype   aa

2 generation   

1

Normal    heterozygous-genotype   Aa

2

Normal    heterozygous-genotype   Aa

3

Normal    homozygous-genotype   AA

4

Affected    homozygous-genotype   aa

5

Normal    heterozygous-genotype   Aa

6

Normal    heterozygous-genotype   Aa

7

Normal    heterozygous-genotype   Aa

8

Normal    homozygous-genotype   AA

 Probability and genetic counseling (OPEN BOXES OR CIRCLES ARE NORMAL PHENOTYPE; CLOSED BOXES OR CIRCLES ARE ALBINO) Please calculate the probability to produce
 Probability and genetic counseling (OPEN BOXES OR CIRCLES ARE NORMAL PHENOTYPE; CLOSED BOXES OR CIRCLES ARE ALBINO) Please calculate the probability to produce
 Probability and genetic counseling (OPEN BOXES OR CIRCLES ARE NORMAL PHENOTYPE; CLOSED BOXES OR CIRCLES ARE ALBINO) Please calculate the probability to produce
 Probability and genetic counseling (OPEN BOXES OR CIRCLES ARE NORMAL PHENOTYPE; CLOSED BOXES OR CIRCLES ARE ALBINO) Please calculate the probability to produce

Get Help Now

Submit a Take Down Notice

Tutor
Tutor: Dr Jack
Most rated tutor on our site