Use the product rule to expand each logarithmic expression l
Solution
1)
a) log3(3*8) = log33 + log38 = 1 + log38
b) log(10y) = log10 + logy = 1 + logy
c) ln(5e3) = ln5 + 3lne = 3 + ln5
A) log6(7*11) = log67 + log611
B) log(100x) = log100 + log x = 2 + log x
C) ln(10e2) = ln10 + 2lne = 2 + ln10
2)
a) log(10/x) = log10 – log x = 1 – log x
b) log(100/9) = log 100 – log 9 = 2 – 2log3
c)ln(e2/9) = 2 – ln9
A)
B)log(a/100) = log a - 2
C) ln(e3/10) = 3 – ln10
