Material properties Elongation at fracture 1 Tensile strengt

Material properties:

Elongation at fracture =1%

Tensile strength, Sut =30KSI

Compressive Strength, Suc = 105KSI

Modulus of Elasticity E = 14E6 PSI

Poisons Ratio V=0.211

4 b) 4 b) SHAFT 0,5 PRESS FIT Tokua@ SHAFT (A) 15 PRESS FIT To HuB®. BASED DA THE DIMENsous LISTED HERE, DETEAPINE THE SAFATY FAuTO FOR THE HUB ) vs1ng A SUITABLE FALURE THEORy SHAFT (A) OD= 2.0025 CARB STEEL MATERIAL

The formula to find out factor of safety = Maximum stress / Working or design stress

In hub while making tight fit , both tensile and compressive stress are developed with respective strengths , here compressive strength divides with tensile strength will get a factor of safety of material

So here factor of sfety is 105 / 30 = 3.5

$Material properties: Elongation at fracture =1% Tensile strength, Sut =30KSI Compressive Strength, Suc = 105KSI Modulus of Elasticity E = 14E6 PSI Poisons Ratio$

Material properties Elongation at fracture 1 Tensile strengt

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