tansin12u5Solutiontansin12u5 let sin12u5 p sinp 2u5 opposite

tan(sin-1(2u/5))

tan(sin^-1(2u/5))

let sin^-1(2u/5) =p

=>sin(p) =2u/5

opposite side =2u ,hypotenuse =5

5²=(2u)²+ adjacent side²

adjacent side²=25-4u²

adjacent side=(25-4u²)

tan(sin^-1(2u/5))

=tan(p)

=opposite side/adjacent side

=2u_/(25-4u²)

therefore tan(sin^-1(2u/5)) =2u_/(25-4u²)