Let F be an extension field of K and let u F Show that Ku2
Let F be an extension field of K and let u F. Show that K(u^2 ) K(u) and [K(u) : K(uˆ2 )] = 1 or 2.
Solution
K(u2) is a subset of K(u).
Essentially, you just need to note that since a is in K(u), u2 is in K(u). Any further details you should be able to work out.
Claim: [K(u) : K(u2)] = 1 or 2
Here, just note that
g(x) = x2 - u2
is a polynomial with coefficients in K(u2) such that a is a root.
By the first claim,
K(u) = ( K(u2) ) (u),
Hence,
[ K(u) : K(u2) ] <= deg g = 2.
![Let F be an extension field of K and let u F. Show that K(u^2 ) K(u) and [K(u) : K(uˆ2 )] = 1 or 2.SolutionK(u2) is a subset of K(u). Essentially, you just need Let F be an extension field of K and let u F. Show that K(u^2 ) K(u) and [K(u) : K(uˆ2 )] = 1 or 2.SolutionK(u2) is a subset of K(u). Essentially, you just need](/WebImages/17/let-f-be-an-extension-field-of-k-and-let-u-f-show-that-ku2-1033324-1761535812-0.webp)