we want to test on basis n35 determination VALENCIA OLLEGE 2

VALENCIA OLLEGE 2 we want to test on the bass or n·35 de \"teoosem of ked-e EGN 2440 signficance, whether the thermal conductivey of tro Fal 2015 is 0340, as has been claimed From studies, we can expect that on 9 owed n·mi the variability of such determinations is given by Hybrid / Lectures - 0010 We want to reject the n hypothess the mean of the ess or significantly greater than 0 340 Suppose T 2 30-4:30 West Campus that the mean ofthe 35 determinations-0343 As me 11-237 Prof Myra Monreal (a) Givens (2 points) (b) Null and Alternative Hypothesis (3 points) (c) Identify Test Distribution (2 points) (d) Calculate Test Value (3 points) (e) Graph (3 points) Conksion ( 2 points) Emai Office Hours WC 11-237 Page 3 of 7

Solution

Set Up Hypothesis
Null, H0: U=0.34
Alternate, H1: U!=0.34
Test Statistic
Population Mean(U)=0.34
Given That X(Mean)=0.343
Standard Deviation(S.D)=0.01
Number (n)=35
we use Test Statistic (Z) = x-U/(s.d/Sqrt(n))
Zo=0.343-0.34/(0.01/Sqrt(35)
Zo =1.7748
| Zo | =1.7748
Critical Value
The Value of |Z | at LOS 0.05% is 1.96
We got |Zo| =1.7748 & | Z | =1.96
Make Decision
Hence Value of |Zo | < | Z | and Here we Do not Reject Ho
P-Value : Two Tailed ( double the one tail ) - Ha : ( P != 1.7748 ) = 0.0759
Hence Value of P0.05 < 0.0759, Here We Do not Reject Ho

[ANSWERS]
1. H0: U=0.34 , H1: U!=0.34
2. Zo =1.7748
3. Do not Reject Ho