Exercise 932 METHODS AND APPLICATIONS Bayus 1991 studied the
Exercise 9.32 METHODS AND APPLICATIONS
| Bayus (1991) studied the mean numbers of auto dealers visited by early and late replacement buyers. Letting be the mean number of dealers visited by all late replacement buyers, set up the null and alternative hypotheses needed if we wish to attempt to provide evidence that differs from 4 dealers. A random sample of 100 late replacement buyers yields a mean and a standard deviation of the number of dealers visited of |
Solution
>>
H0 : = 4 versus Ha : 4
>>
t = ( X - X-bar) / (Sample SD / sqrt(n))
= (4.26 -4 ) / (0.52/sqrt(100))
= 5 Answer
>> dF = 100-1 = 99
t/2 =0.0005= 3.174
Critical value is less than t value
Therefore , Greater than 4 Answer
| t/2 = 0.05= 1.66 | |
| t/2 =0.025= 1.984 | |
| t/2 =0.005= 2.626 | |
| t/2 =0.0005= 3.174 Critical value is less than t value Therefore , Greater than 4 Answer |
