If you are given right triangle ABC with angle B being the r

If you are given right triangle ABC, with angle B being the right angle, and you are given that cos A = 40/41, then find: sin C = tan A = cos C = sin A =

cos A= 40/41

Here adjacent= 40 hypotenuse=41

opposite=sqrt(1681-1600)=9

a. sin C= opposite/hypotenuse= 40/41

b. tan A= opposite/adjacent = 9/40

c. cos C= adjacent/hypotenuse= 9/41

d. sin A= opposite/hypotenuse= 9/41

If you are given right triangle ABC, with angle B being the right angle, and you are given that cos A = 40/41, then find: sin C = tan A = cos C = sin A =Soluti

If you are given right triangle ABC with angle B being the r

Solution

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