The PDF of a uniform failure distribution is ft1b for 0

The PDF of a uniform failure distribution is f(t)=1/b for 0<=t<=b. Find F(t), R(t), lamba(t), MTTF, Tmed, Tmode, and the standard deviation. F(t)=int(f(t)dt), which I came up with F(t)=ln t. Is that correct? It\'s been a long time since I\'ve worked problems like this...

Solution

yes it is correct

The PDF of a uniform failure distribution is f(t)=1/b for 0<=t<=b. Find F(t), R(t), lamba(t), MTTF, Tmed, Tmode, and the standard deviation. F(t)=int(f(t)

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