Problem 1 For the system shown the force F270 N d 20 m a 30

Problem 1: For the system shown, the force F-270 N, d= 20 m, a = 30°, and b = 650. al The moment Mo of F about O = Problem 2 For the couple shown the force F= 6000 N, b = 40 m, and q = 300 N-m (Counter-Clockwise) The moment of the couple = N-m (Counter-Clockwise)

Solution

Cos b = x/d

x=d cos b = 20* cos 65

=8.45 m

Y=d sin b = 20* sin 65

=18.13 m

Mo= F cos a * y- F sin a * x

=270 * cos 30 * 18.13 -270*sin 30*8.45

=3097.6 N.m