4X075 U 2100 45 500 R350 END PLATE 01100 GAT 04000 b 0800010
Solution
solution:
1..Consider a Horizontal circular or cylindrical Tubing and cut the cross section in two half. So right side picture is half section seen from front side and left side is the side view.
Side view and Front section view respectively.
2 ..
a] Wall thickness = 0.75 in
b] Material for the tube body -- SAE 100 Seam less [ material specified at the bottom right corner]
and for all other parts SAE 30705
3-----
Basic Dia for A = 8.0 in
Basic Dia for B = 7.25 in
Basic Dia for C = Db - t/2 = 7.25 in - 0.75 in/2 = 6.875 in
4.....
Maximum dia : 11 in
Minimum Dia : 1 in [ID of bolt holes]
5....
E= Maximum Height = 15 + 3.5 = 18.5 in
F = Maximum Length = 18.5 +2 = 20.5 in
6...
Upper Limit = 0.002 in = 0.0508 mm
Lower Limit = 0.001 in = 0.0254 mm
7..
4X phi0.75 and phi 1.0 in
Minimum Dia = 0.75 in
Minimum Depth = 4 in
8...
Basic size = R = 3.5 in Radius
9...........
Surface Roughness symbol is present at 3 surfaces.So 3 Surfaces need to be machined
10..
Max dimensions of circular end Plate :
L = 20.5 in
W = 15 in
T = 15 in

