The problem must be solved using Richardson extrapolation Co

The problem must be solved using Richardson extrapolation!

Consider the date points Estimate f\'(0) using an O.(.01^3) approximation. Compare this to true value f\'(0) = 2.000000.

Solution

f\'(0)= 1.0200502 -1.000000 / 0.001 -0

f\'(0) = 0.0200502 /0.01

f\'(0)= 2.0052

now comparing the true value of f\'(0) with

the true valus is more 0.0052

so error = 5.2x10^-3