Homework SourseActivity Normal Time Crash Time Cost per day to crash A 6 6
Activity
Normal Time
Crash Time
Cost per day
to crash
A
6
6
---
B
10
8
$100
C
5
4
$300
D
4
1
$700
E
9
7
$500
F
2
1
$650
Determine which activities should be crashed to shorten the project by 1 day
Determine which activities should be crashed to shorten the project by 2 days.
Crash activity B by 1 day and Activity C by 1 day.
Crash activity E by 2 days.
Crash activity C by 1 day and activity E by 1 day.
Crash activity B by 2 days.
| Activity | Normal Time | Crash Time | Cost per day to crash |
| A | 6 | 6 | --- |
| B | 10 | 8 | $100 |
| C | 5 | 4 | $300 |
| D | 4 | 1 | $700 |
| E | 9 | 7 | $500 |
| F | 2 | 1 | $650 |
Solution
Under normal times the two paths that can be followed are:
ABF = 15 (under normal times)
CDEF = 13 (under normal times)
To shorten the project by one day, any of the activities could be crashed except for A, since the maximum reduction in A possible is zero.
It would be wisest to shorten B as it is the least expensive to crash.
For the next question we determine each of the options:
Hope this helps.
| Activity | NT | CC | Cost | Max Redn |
| A | 6 | 6 | --- | 0 |
| B | 10 | 8 | $100 | 2 |
| C | 5 | 4 | $300 | 1 |
| D | 4 | 1 | $700 | 3 |
| E | 9 | 7 | $500 | 2 |
| F | 2 | 1 | $650 | 1 |
