Two airplanes start toward each other at the same time from

Two airplanes start toward each other at the same time from airports located 1950 km apart. One plane flies at an average speed of 360 km/h. What should the average speed of the plane be if they meet in 3 hours? Show all work.

Solution

This is a RTD problem. Here is the table based on given information:
airplane . . . . . . . . .rate . . . . . . . . .time . . . . . . . . .distance
A . . . . . . . . . . .. . . .360 . . . . . . . . .3 . . . . .. . . . . .. . 1080
B . . . . . . . . . . . . . . .R . . . . . . . . . . .3 . . . . . . .. . . . .. . 3R
totals . . . . . . .. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .. 1950
The distance of A + distance of B = total distance. So,
1080 + 3R = 1950
3R = 870
R = 290 km/h