The COP of a refrigerator decreases as the temperature of th
The COP of a refrigerator decreases as the temperature of the refrigerated space is decreased. That is, removing heat from a medium at a very low temperature will require a large work input. Determine the minimum work input required in units of kJ to remove 1 kJ of heat from liquid helium at 3 K when the outside temperature is 300 K.
Solution
TL=3k
TH=300k
cop = TL/(TH-TL)
= 3/(300-3)
= 0.0101
cop = Refregeration effect/work input
0.0101 = 1/work input
work input = 1/0.0101
= 99kJ
from this example
yes, removing heat from medium at a very low temperature requires large work and cop also decreses drastically
