So lets say I am rolling a dice untill I get three ones What
So lets say I am rolling a dice untill I get three one\'s. What distribution would I use to find the probability of rolling the dice at least six times?
Solution
Given that rolling a dice untill I get three one\'s.
Let X be a random variable number of failuare preceeding third throw of die appear one.
P(success) = 1/6 = 0.1667
P(failuare) = 1 - 0.1667 = 0.8333
X follows Negative binomial distribution with parameter r and P.
where r is number of successes =3
P=probability of success appearing 1
P(X>=6) = 1 - P(X<6)
The p.m.f. for Negative binomial distribution is ,
P(X =x) = (x+r-1 C x) * px * qr
we have given x+r = 6
And we have to find P(X>=6)
