A circular saw blade of diameter 0230 m starts from rest In

A circular saw blade of diameter 0.230 m starts from rest. In a time interval of 6.05 s it accelerates with constant angular acceleration to an angular velocity of 136 rad/s .

A: Find the angular acceleration.

B: Find the angle through which the blade has turned.

Solution

a) Angular acceleration = w / t

= 136 / 6.05

= 22.48 rad/s²

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b) Angle through which blade has turned

= (136²) / (2 * 22.48)

= 411 radians