15 Let PA 053 PB 028 and PA B 015 Solutiongiven PA 053
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| Let P(A) = 0.53, P(B) = 0.28, and P(A ? B) = 0.15. |
Solution
given P(A) = 0.53, P(B) = 0.28, and P(A and B) = 0.15.
a)
P(A|B) = P(A and B)/P(B) = 0.15/0.28 = 0.5357
b)
P(A U B) = P(A)+P(B) -P(A and B) = 0.53+0.28-0.15 = 0.66
c)
P((A U B)c) = 1- P(A U B) = 1 -0.66 = 0.34
