Consider the following Assuming no missing principal maxima

Consider the following: Assuming no missing principal maxima, how many secondary maxima will there be between principal maxima in a 5-slit diffraction slide? A numeric value is expected and not an expression.

Solution

If there are n slits, then n-2 secondary maxima will be present between any two principle maxima.

So For a 5 slit experiment, 3 secondary maxima will be present

M = 3