Please show all work for this solution with an explanation H

Please show all work for this solution with an explanation.
How many different letter arrangements can be made from the letters in the word BOOKKEEPER?

Solution

In \"BOOKKEEPER\", there are 10 letters, and

1 B
2 0
2 K
3 E
1 P
1 R

By permutations of like objects,

#ways = 10! / [1! 2! 2! 3! 1! 1!] = 151200 [answer]