Two individuals with the following genotypes AaBbCcDdeeFFX A

Two individuals with the following genotypes AaBbCcDdeeFFX AaBbCcDdEeff mate. They produce 1500 offspring. How many offspring would have the following genotypes? Assume independent assortment of these six genes aabbccddeeff 216 AabbScDdEeFf 1331 AABBCCDDEEFf343 AaBBccDdeeFf 729 AaBBCCddeeFf 512

Solution

Answer:

AaBbCcDdeeFF x   AaBbCcDdEeff

Aa x Aa = AA (1/4), Aa (1/2) & aa (1/4)

Bb x Bb = BB (1/4), Bb (1/2) & bb (1/4)

Cc x Cc = CC (1/4), Cc (1/2) & cc (1/4)

Dd x Dd= DD (1/4), Dd (1/2) & dd (1/4)

ee x Ee = Ee (1/2) & ee(1/2)

FF x ff = Ff (1)

1). aabbccddeeff = ¼ * ¼ * ¼ * ¼ * ½ * 0 = 0 (1500) = 0

2). AabbCcDdEeFf = ½ * ¼ * ½ * ½ * ½ * 1 = 1/64 (1500) = 23

3). AABBCCDDEEFf = ¼ * ¼ * ¼ * ¼ * 0 * 1 = 0 (1500) = 0

4). AaBBccDdeeFf = ½ * ¼ * ¼ * ½ * ½ * 1 = 1/128 (1500) = 12

5) AaBBCCddeeFf = ½ * ¼ * ¼ * ¼ * ½ * 1 =1/256 (1500) = 6