Given the Phasor current I 11Z 90degreemA at a linear frequ

Given the Phasor current I = 11Z. -90degree(mA) at a (linear) frequency of 1 MHz. what is the corresponding tune function? (f) = 11cos(2TT times10t + 90degree) (mA) (f) = 11cos(10^6(- 90degree) (mA) (f) = -y11 (mA) (f) = 11cos(2TT x106f - 90degree) (mA)

Solution

w=2*pi*f,where f=10^6

so 11cos(wt-90) mA

option d)