The cylinder shown in Fig 1615a rolls without slipping on th

The cylinder shown in Fig. 16-15a rolls without slipping on the surface of a conveyor belt which is moving at 2 ft/s. Determine the velocity of point A. The cylinder has a clockwise angular velocity omega = 15 rad/s at the instant shown. Kinematic Diagram. Since no slipping occurs, point B on the cylinder has the same velocity as the conveyor, Fig. 16-156. Also, the angular velocity of the cylinder is known, so we can apply the velocity equation to B, the base point, and A to determine v_A.

Solution

Instantaneous center of velocity is useful for Problem of the mechanisms where, one link is always fix.

The problem that you have posted, there is no fix member available in it, so one can not use cannedy\'s principle for finding remaining instantaneous center of velocity.

That is why this problem can not be solve by instantaneous senter of velocity.

Another problem is that, the rolling motion is higher order pair in the motion (line contact) and instantaneous center method is not useful for analysing it.

It\'s better to solve it by vector method.

Hope It will useful for you.

Have a Nice Day ....

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