Find the equivalent impedance of the circuit below if the op

Find the equivalent impedance of the circuit below if the operating frequency is 60Hz. For b), c) and d), consider that the circuit is connected to a voltage generator v(t)=2 sm(2pi60 t) V (with positive terminal connected to the node A): b) Find the phasor I and the corresponding current i(t) that enters the node A: c) Find the phasor V_L and the corresponding voltage over the inductor: (TIP: can you use voltage divider?) d) Now that you know the phasor V_L, find the phasor V_c and the corresponding voltage over the capacitor (TIP: There are many ways to do this. One is way to compute the current over the capacitor branch)

Solution

xl=jwl=j2*3.14*60*10*10^-3=j3.7699 ohms

xc=1/(jwc)=1/(j2*3.14*60*500*10^-6)=-j5.305 ohms

z=2+[(4-j5.305)*j3.7699]/[4-j5.305+j3.7699]=5.846<58 ohms

total current i=2<0/(5.846<58)=0.342<-58 amps

voltage across inductor=2<0-0.342<-58 *2=1.737<19.5 volts