Assuming that the heights are normally distributed with mean

Assuming that the heights are normally distributed with mean of 63 inches and standard deviation 2 inches, what percentage of women are taller than 57 inches? A) 50% B)99.9% C) 0.1% D) 15.9%

Solution

mean = m = 63 inches

standard deviation = sd =2 inches

z= (x-m)/sd

P(x>57) = 1- P(x<57)

P(x>57) = 1 - P(z<-3)

P(x>57) = 1 - 0.0013

P(x>57) = 0.9987

so, 99.87 % is similar to 99.9%

option B is your answer

Assuming that the heights are normally distributed with mean of 63 inches and standard deviation 2 inches, what percentage of women are taller than 57 inches? A

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