Homework SourseF 2xx2y2 cosy 2yx2y2sinxSolution Hi Fx 2x x2 y2 cosy F
F = (2x/x2+y2 - cosy, 2y/x2+y2+sinx)![F = (2x/x2+y2 - cosy, 2y/x2+y2+sinx)Solution Hi, F(x) = [(2x) / (x^2 + y^2)] - cos(y) F(y) = [(2y) / (x^2 + y^2)] + sin(x) F\'(x) = - (2 (x^2-y^2))/(x^2+y^2)^2](/WebImages/18/f-2xx2y2-cosy-2yx2y2sinxsolution-hi-fx-2x-x2-y2-cosy-f-1035922-1761537506-0.webp "F = (2x/x2+y2 - cosy, 2y/x2+y2+sinx)Solution Hi, F(x) = [(2x) / (x^2 + y^2)] - cos(y) F(y) = [(2y) / (x^2 + y^2)] + sin(x) F\'(x) = - (2 (x^2-y^2))/(x^2+y^2)^2")
Solution
Hi, F(x) = [(2x) / (x^2 + y^2)] - cos(y) F(y) = [(2y) / (x^2 + y^2)] + sin(x) F\'(x) = - (2 (x^2-y^2))/(x^2+y^2)^2 F\'(y) = (2 (x^2-y^2))/(x^2+y^2)^2 As you can see they are not equals because the derivative of the f(x) is negative and the derivative of y(x) is positive F is not conservative