There are multiple alleles that determine eye color in rabbi

There are multiple alleles that determine eye color in rabbits, a⁺ encodes red eyes, a^b encodes bown eyes, and a^w encodes white eyes. These alleles display complete dominance and are presented in their order of dominance (a⁺>a^b>a^w)

a) If an individual were a⁺/a^b, what color would their eyes be?

b) So, if you mated that a⁺/a^b individual wuth one that has white eyes, what are the odds of having a brown eyed bunny?

c) A novel mutation of the gene that produces yellow eyes (a^y) is codominant with a⁺. So what would an a⁺/a^y indivdual look like?

Solution

a) If a+ is dominant over the other two, then one copy of a+ is sufficient to express its red eye phenotype. So if the individual were a+/ab the eye color would be red.

b) cross between a+/ab ( red eyed) X aw/aw white eyes

progeny - 1 a+/aw ( red eyes) : 1 ab/aw ( brown eyes)

50 % of the individual will be brown eyed

c) If the mutation in gene (ay )shows codominance, then a+/ay will show an color intermediate between red and yellow eyes.