At what altitude h above the north pole is the weight of an
At what altitude h above the north pole is the weight of an object reduced to 43% of its earth-surface value? Assume a spherical earth of radius R and express h in terms of R.
Solution
gh = 0.43*g0
G*Me/(Re + h)^2 = 0.43*(G*Me/Re^2)
Re^2 = 0.43*(Re + h)^2
h = ((0.43)^0.5 - 1)*Re
Comment below if you have any doubt.
