The onetoone functions g and h are defined as follows g 8 7

The one-to-one functions g and h are defined as follows. g = {(-8, 7), (1, -1), (3, 9), (8, -8)} h(x) = 3x + 8 Find the following.

g^-1(-8)

The value of x is 8 when y=-8

Therefore g^-1(-8) = 8

h(x)=3x + 8

Let y=h(x)

y= 3x+8

To find the inverse we have to switch x and y and solve for y

x= 3y+8

x-8=3y

Y= (x-8)/3

Therefore

h^-1(x)= (x-8)/3

(hoh^-1)(-4)

h^-1(-4)= (-4-8)/3 = -4

Therefore (hoh^-1)(-4) =h(h^-1(-4)) = h(-4) = 3(-4) +8 =-4