8 An article in the Washington Post on March 16 1993 stated
     8) An article in the Washington Post on March 16, 1993 stated that nearly 45 percent of all Americans have brown eyes. A random sample of   What is the P-value of the test? -statistic for this test? What is the  H_0 : p = 45 Image for 8) An article in the Washington Post on March 16.1993 stated that nearly 45 percent of all Americans have C of I students found 30 with brown eyes.   We test  
  
  Solution
proportion of brown eyes p = 30/78 = 0.3846
standard deviation = sqrt[ p ( 1-p)/n]
= sqrt[ (30 * 48)/(78 * 78 *78)]
= 0.0551
Z-statistic = 0.3846 - 0.45/0.0551
= -1.1869
P-value = 0.1176

