use substitution to solve the system of linear equation xy9z

use substitution to solve the system of linear equation

x+y+9z=-9

x+y+4z=-4

x-5y-2z=-22

x+y+9z=-9

x+y+4z=-4

x-5y-2z=-22

from first equation we get

x=-9-y-9z

substituting this value of x in second equation we get

-9-y-9z+y+4z=-4

z=-1

substituting this value of z in second and third equation

x+y-4=-4

x+y=0

x-5y+2=-22

x-5y=-24

So we have two equations

x+y=0 and x-5y=-24

x+y=0

x=-y

substitute this value of x in x-5y=-24

-y-5y=-24

-6y=-24

y=4

x + y +9z=-9

x +4 -9=-9

x=-4

Therefore the answer is

x=-4, y=4 and z=-1

-6y=