The probability distribution below shows the number of peopl
The probability distribution below shows the number of people (X) waiting in line at Candi’s Coffee Café at 9am on any given weekday.
a. Find P(X=5)
b. Find P(X<5)
c. Based on this data, if you walked into Candi’s Coffee Café at 9am tomorrow, how many people would you expect to see standing in line?
| X | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 |
| P(X) | 0.03 | 0.04 | 0.09 | 0.15 | 0.08 | 0.18 | 0.22 | 0.11 | 0.06 | 0.01 |
Solution
A)
P(x=5) = 0.18 [ANSWER]
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b)
P(x<5) = P(0) + P(1) + P(2) + P(3) + P(4)
= 0.03+0.04+0.09+0.15+0.08
= 0.39 [ANSWER]
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C)
Consider:
Thus,
E(x) = 4.55 [ANSWER]
| x | P(x) | x P(x) |
| 0 | 0.03 | 0 |
| 1 | 0.04 | 0.04 |
| 2 | 0.09 | 0.18 |
| 3 | 0.15 | 0.45 |
| 4 | 0.08 | 0.32 |
| 5 | 0.18 | 0.9 |
| 6 | 0.22 | 1.32 |
| 7 | 0.11 | 0.77 |
| 8 | 0.06 | 0.48 |
| 9 | 0.01 | 0.09 |
