An ant in a room where the length is 20 ft width is 15 ft an
An ant in a room where the length is 20 ft, width is 15 ft and height is 10 ft. The ant is located at one corner of the cube (call it point A), that wants to crawl to the opposite corner of the cube (call it point B). Find the length of the shortest path the ant can take from point A to point B. Note that the ant cannot fly: it must crawl along the walls (i.e., along the surface of the cube). This question can be answered using calculus or without calculus, both is fine but I would rather know the calculus method.
Solution
here ant will crawl first along the diagonal of 20 ft and 15 ft and hence cover distance = 25 ft along diagonal after that it will move along the height .. and hence distance traveled by ant = 25+10 =35ft