Show Work Please Among the 300 employees of a company 240 ar

Show Work Please

Among the 300 employees of a company, 240 are union members, whereas the others are not. If six of the employees are chosen by lot to serve on a committee that administers the pension fund, find the probability that four of the six will be union members.

Solution

Total employees = 300

Union members = 240

There are two outcomes, either union member or not and each person is independent.

Hence prob for 4 of the 6 to be union members

= Binomial prob for 4 successes in 6 success with p = 240/300 = 0.8

= 0.24576