ASSEMBLY LANGUAGE Can you please review these answers Thank

ASSEMBLY LANGUAGE

Can you please review these answers

Thank You!

1. Convert 6605₇ => n ₈ =   4465              

2.   Convert 240311₅   => n₁₆ = 227F   

3.   Convert 2361511₉ => n₁₆ =   138A1B

4. By matching convert the below binary number to the base 8:   

        1 1 0 1 1 0 1 1 0 1 1 1 0 1 1 1 0 11 0 1 11 0 0 11 0 1 0 1 0 1 1₂ => n₈ = 155567334653

5. Simplify : (134₇ + 2131₇)*101₇   =>     n₁₆    = A24E      

6. 5329₁₀ => n₃ = 21022101

7. (10₄)⁵ - 1 = n₄   = 33333    => n₁₆   = 3FF

8. Convert 45AF₁₆     => N_3.

    220110201

9. Complete this table. Make sure all cells that contain numbers are filled.

PSEUDO-CODE INSTRUCTIONS  

X

Y Z

X: =7 7

Y := -12

7

-12

Z := 13

7

-12

13

IF (X + Y + Z) <> X*Y THEN

7

-12

13

BEGIN

7

-12

13

X : = (X – Y) ÷ X

2

-12

13

Y := X – 3 * Y

2

38

13

Z : = X + 5

2

38

7

END

2

38

7

IF (X - Y + Z) <> X +Y THEN

2

38

7

BEGIN

2

38

7

X : = 2 * (X – Y) ÷ X

-36

38

7

Y := X – 3 * Z

-36

-57

7

Z : = X + 2

-36

-57

-34

END

-36

-57

-34

10. (212₃ + 2222₃)*101₃ =>    n₁₀= 1030

11. The instructions

X := 3                                                                

X :=X*X

X :=X+X

X :=X*X

will cause the final value of X to be = 324

12.

X := 12

Y := 15

Z := 5

Z := X

X := Y

Y := Z

The above sequence of commands will exchange the values in the variables, resulting finally in

Answer: X= 15;    Y = 12;         Z = 12

13.

W:=7

U:= 2

W:= 5 + (W*(W + U÷W) + 2)÷2

T := W

The above sequence of instructions will store 30 in T

14.   

X := 3

X := 2*X - X                          

X := 2*X + X

X := 2*X - X              

X := 2*X + X

X := 2*X - X

X := 2*X + X                                     

Y := 2*X

The above sequence of instructions will store   162     in Y.

15.

IF X < 0 THEN

BEGIN

X : = -1*X

END

IF 2*(X÷2) <> X THEN

BEGIN

X := X - 1

END

ELSE

BEGIN

X : = X + 1

END

The purpose of writing the above algorithm is

If X is negative, make it positive.   If X is odd, subtract one from X;

If X is negative, make it positive.   If X is even, add one to X.

(a.)    TRUE          (b.)   FALSE        (A)True

16.

Complete the table below. Make sure you fill in all cells that contain numbers.

PSEUDO-CODE INSTRUCTIONS  

X1

X2

X3

COUNT

X1 := 5

5

X2 := 12

5

12

   X3 := -2

5

12

-2

COUNT := 0

5

12

-2

0

IF X1 < 0 THEN

BEGIN

COUNT := COUNT + 1

END

5

12

-2

0

IF X2 < 0 THEN

BEGIN

COUNT := COUNT + 1

END

5

12

-2

0

IF X3 < 0 THEN

BEGIN

COUNT := COUNT + 1

END

5

12

-2

1

                                                                                                            

17.

Complete the following table. Make sure all cells that contain numbers are filled.

(Note: The symbol   ^ is to raise a number to a given power. Ex. 2 ^3 = 8).

  

PSEUDO-CODE INSTRUCTIONS  

N10

Q

  

N8

R

K

BASE

N10 := 2304

2304    

BASE := 8

2304

N8 := 0

2304

0

8

K : = 0

2304

0

0

8

R :=   N10 MOD BASE

2304

0

0

0

8

Q:= (N10 - R)÷BASE

2304

288

0

0

0

8

N8:= N8 + R*10^K

2304

288

0

0

0

8

N10 := Q

288

288

0

0

0

8

K := K + 1

288

288

0

0

1

8

R :=   N10 MOD BASE

288

288

0

0

1

8

Q:= (N10 - R)÷BASE

288

36

0

0

1

8

N8 := N8 + R*10^K

288

36

0

0

1

8

N10 := Q

36

36

0

0

1

8

K := K + 1

36

36

0

0

2

8

R :=   N10 MOD BASE

36

36

0

4

2

8

Q:= (N10 - R)÷BASE

36

4

0

4

2

8

N8 := N8 + R*10^K

36

4

400

4

2

8

N10 := Q

4

4

400

4

2

8

K := K + 1

4

4

400

4

3

8

R :=   N10 MOD BASE

4

4

400

4

3

8

Q:= (N10 - R)÷BASE

4

0

400

4

3

8

N8:= N8 + R*10^K

4

0

4400

4

3

8

N10 := Q

0

0

4400

4

3

8

K := K + 1

0

0

4400

4

4

8

18. What is the purpose of writing the following algorithm:

T := N1

IF N2 < T THEN

BEGIN

T := N2

END

IF N3 <T THEN

BEGIN

T := N3

END

Z := T

(a.).    To assign the lowest value to Z         (b.)    To assign the highest value to Z

Answer A.

19. What does the programmer what to find out from the following algorithm:

IF 2*(X÷2) = X THEN

BEGIN

EVEN := 1                            

END

IF 2*(X÷2) <> X THEN

BEGIN

ODD:= 1

END

To find is it number even or odd

20.

Complete the following table. Make sure all cells with numbers are filled.

INSTRUCTIONS

X1

X2

X3

TEMP

X1:= 7

7

X2:= 2

7

2

X:3= 10

7

2

10

IF X1 < X2 THEN

7

2

10

BEGIN

7

2

10

TEMP := X1

7

2

10

X1 := X2     

7

2

10

X2 := TEMP

7

2

10

END

7

2

10

IF X2 < X3 THEN

7

2

10

BEGIN

7

2

10

TEMP := X2

7

2

10

2

X2 := X3     

7

10

10

2

X3 := TEMP

7

10

2

2

END

7

10

2

2

PSEUDO-CODE INSTRUCTIONS	X	Y Z
X: =7 7
Y := -12	7	-12
Z := 13	7	-12	13
IF (X + Y + Z) <> X*Y THEN	7	-12	13
BEGIN	7	-12	13
X : = (X – Y) ÷ X	2	-12	13
Y := X – 3 * Y	2	38	13
Z : = X + 5	2	38	7

Solution

The solution provided for question no 1 to 15 are correct.

i am giving you the stepwise results of two of the questions:

14) X := 3

X := 2*X - X =3

X := 2*X + X =9

X := 2*X - X =9

X := 2*X + X =27

X := 2*X - X =27

X := 2*X + X =81   

Y := 2*X =162

12)

X := 12

Y := 15

Z := 5

Z := X (Z=12)

X := Y (X=15)

Y := Z (Y=12)