Def onectuuersstrand names sequences str list of str list of

Def one_ctuuers(strand, names, sequences): \"\"\"(str, list of str, list of str) rightarrow list of (str, int) tuples The parameters are the same as for match_enzymes. Return a list of tuples representing the 1-cutters for the DNA strand that is the first parameter. The first item of each tuple is the name of a restriction enzyme and the second item is the index (in the DNA strand) of the one restriction site that the enzyme cuts. >>>one_ctuuers (\"ATTGCGAGCT\", [\"Alul\", \"Kpnl\"], [\"AGCT\", \"GGTACC\"]) [(\"Alul\", [6])) >>>one_ctuuers (\"CCCGGCCAGCTGGCC\", [\"Haelll\", \"Alul\"], [\"GGCC\", \"AGCT\")) [(\"Haelll\", [3]), (\"Alul\", [7])] >>>one_Ctuuers (\"GTCGACTTATCGA\", [\"Taql\'\\ \"Kpnl\"], [\"TCGA\", \"GGTACC\")) [(\"TaqI\", [1])]

Solution

def one_ctuuers( strand, names, sequences ):

p= []

for i in range( len( names ) ):

findindexes = binding( strand, sequences[ i ] )

p += [ ( names[ i ], findindexes ) ]

return p

def binding(stringA, stringB ):

checkindexes = []

i = 0

while i < len( stringA ):

# Firstly we will compare the string A cut from the index i to whatever size string B is

# now if the strings are equal we will be adding the index to the list and increment the value of i depending on the length of stringB

if stringA[ i : i + len( stringB ) ] == stringB:

checkindexes += [ i ]

i += len( stringB ) - 1

i += 1 # now we will go to next index

return checkindexes