Find the length of the curve y1279x2632 from x0 to x6Solutio
Find the length of the curve y=1/27(9x^2+6)^3/2 from x=0 to x=6
Solution
y = (9x2 + 6)3/2/27
y\' = x(9x2 + 6)1/2
1 + y\'2 = 1 + x2(9x2 + 6) = (3x2 + 1)2
(1 + y\'2) = 3x2 + 1
arc length = 06 (1 + y\'2) = 06 (3x2 + 1) dx = x3 + x |06 = 222
