Homework SourseR1 165 R2 275 R3 385 a the current in each resistor Gi
| I1 = | 1 A |
| I2 = | 2 A |
| I3 = | 3 A |
(b) the power consumed by each resistor
| P1 = | 4 W |
| P2 = | 5 W |
| P3 = | 6 W |
(c) the power supplied by the emf device
7 W
| I1 = | 1 A |
| I2 = | 2 A |
| I3 = | 3 A |
Solution
Emf E = 4.3 volt
R1 = 16.5
R2 = 27.5
R3 = 38.5
R2 andR3 are in series.Resultant resistance R = R2+R3
R = 27.5 +38.5
= 66
Current through R2 andR 3 is i = E / R
= 4.3 volt /66
= 0.06515 A
Current through R1 is i \' = E / R1
= 4.3 volt /16.5
= 0.2606 A
= 0.261 A
Current through R2 is = 0.0652 A
Current through R3 is = 0.0652 A
(b).Power consumed by R1 is P1 = i \' 2 R1
= 0.2606 2 x 16.5
= 1.12 watt
.Power consumed by R2 is P2 = i 2 R2
= 0.06515 2 x 27.5
= 0.117 watt
Power consumed by R3 is P3 = i 2 R3
= 0.06515 2 x 38.5
= 0.163 watt
(c).R and R1 are in parallel.
So, equivalent reistance R \' = (RxR1)/(R+R1)
= (66x16.5)/(66+16.5)
= 13.2 ohm
the power supplied by the emf device = E 2 /R \'
= 4.3 2 /13.2
= 1.4 watt
