Homework Soursefind the particular solution of the differential equation th
find the particular solution of the differential equation that satisfies the initial condition. dy/dx= e^(x+y). x(1)=0
Solution
dx/dy = e^(x + y)
dx/dy = e^x(e^y)
e^-x dx = e^y dy
? e^-x dx = ? e^y dy
-e^-x = e^y + c
-e^-1 = e^0 + c
-1/e = 1 + c
-1/e - e = c
-e^-x = e^y - 1/e - e
